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CONVERSION OF GALVANOMETER INTO AMMETER AND VOLTMETER PDF

Conversion of a Galvanometer into Ammeter and Voltmeter. Voltmeter: It is a high resistance galvanometer, used to measure potential. Conversion of a galvanometer into voltmeter & Ammeter. 1. KAMALJEETH INSTRUMENTS. Experiment S. GALVANOMETER AND ITS. CONVERSION . Voltmeter and Ammeter. Objective: (a) To convert a galvanometer into a voltmeter reading up to V volts and calibrate it. (b) To convert a galvanometer into an.

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Anyway, I do understand how a galvanometer is converted into an ammeter but it’s logic doesn’t seem to add up. Where E is the e. Galvanometer is too sensitive therefore is modified to be anr to measure current instead of only detect it.

Post Your Answer Discard By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policyand that your continued use of the website is subject covnersion these policies. I understand why the shunt resistance has to be of a smaller value and the resistance of voltmeter has to be of a really greater value but what I fail to comprehend is how can we successfully measure current when the deflection of the needle is going to always be voltmwter due to the passage of Ig current.

Ammetdr of needle is not always going to be maximum. How to convert a Galvanometer into an Ammeter? Retrieved 1 Januaryfrom amrita. For this purpose, it is put in series with the circuit in which the current is to be measured.

Conversion of Galvanometer to Ammeter. Remember that galvanomfter galvanometer doesn’t “hog” all the current if the current is a low value. Sign up using Email and Password. Galvanometer Ammeter Figure of merit Shunt resistance How a galvanometer can be converted into an ammeter.

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The current for full scale deflection through it is lets say Ig. The deflection is proportional to the current passed. It has a coil pivoted or suspended between concave pole faces of a strong laminated horse shoe magnet. For ex – an ammeter which can measure current up to 1 A will use a larger value of Rs as compared to an ammeter which can measure a current up to A. Whiskeyjack 3, 2 17 Home Questions Tags Users Unanswered.

If Ig is less than Ig maxthe needle will stay somewhere in between. I am 12th grader just in case. Maximum deflection occurs at Ig max.

Post as a guest Name. A galvanometer is a device used to detect feeble electric currents in a circuit. It can be converted into an ammeter by connecting a low resistance called shunt resistance in parallel to the galvanometer. What is figure of merit of a galvanometer? Note that whatever current galvanometef flowing in the circuit being measured that the current will always split 3: Email Required, but never shown.

Let G be the resistance of the galvanometer and Ig be the current for full scale deflection in the galvanometer, the value of the shunt resistance required to convert the galvanometer into an ammeter of 0 to I ampere is.

The galvanometer coil has a moderate resistance about ohms and the galvanometer itself has a small current carrying capacity 1 mA.

An ammeter is a device used for measuring large electric currents in circuits. Ruqaiya Naeem 13 3. Sign up or log in Sign up using Google. You understood this part wrong.

shunt – Converting a galvanometer into an Ammeter – Electrical Engineering Stack Exchange

I understand why the shunt resistance has to be of a smaller value and the resistance of voltmeter has to be of a really greater gapvanometer but what I fail to comprehend is how can we successfully measure current when the deflection of the needle is going to always be maximum due to the passage of Ig ameter Remember that the galvanometer doesn’t “hog” all the current if the current is a low value.

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Now Rs is of such a value that Ig passes through the galvanometer and the remaining current I-Ig passes through the shunt resistance. To convert the given galvanometer of known resistance and figure of merit into an ammeter of desired range and galvamometer verify the same.

It is represented by the symbol k and is given by the equation.

Our Objective:

The maximum current that the ammeter produced can measure is lets say I and shunt resistance is Rs. I understand why the shunt resistance has to be of a smaller value and the resistance of voltmeter has to be of a really greater value but what I fail to comprehend is how can we successfully measure current when the deflection of the needle is going to always be maximum due to the passage of Ig current which is the current that causes maximum deflection.

When an electric current passes through the coil, it deflects. Thus, to measure large currents it is converted into an ammeter. This is what I know so far.